#jsDisabledContent { display:none; } My Account | Register | Help

# Duane–Hunt law

Article Id: WHEBN0022913171
Reproduction Date:

 Title: Duane–Hunt law Author: World Heritage Encyclopedia Language: English Subject: Collection: X-Rays Publisher: World Heritage Encyclopedia Publication Date:

### Duane–Hunt law

Spectrum of the X-rays emitted by an X-ray tube with a rhodium target, operated at 60 kV. The continuous curve is due to bremsstrahlung, and the spikes are characteristic K lines for rhodium. The Duane–Hunt law explains why the continuous curve goes to zero at 21 pm.

The Duane–Hunt law, named after the American physicists William Duane and Franklin Hunt,[1] gives the maximum frequency of X-rays that can be emitted by Bremsstrahlung in an X-ray tube by accelerating electrons through an excitation voltage V into a metal target.

The maximum frequency νmax is given by[2]

\nu_{\rm max} = \frac{eV}{h}\,

which corresponds to a minimum wavelength

\lambda_{\rm min} = \frac{hc}{eV}

where h is Planck's constant, e is the charge of the electron, and c is the speed of light. This can also be written as:

\lambda_{\rm min} \approx \frac{1239.8 \text{ pm}}{V\text{ in kV}} \,.

The process of X-ray emission by incoming electrons is also known as the inverse photoelectric effect.

## Explanation

In an X-ray tube, electrons are accelerated in a vacuum by an electric field and shot into a piece of metal called the "target". X-rays are emitted as the electrons slow down (decelerate) in the metal. The output spectrum consists of a continuous spectrum of X-rays, with additional sharp peaks at certain energies (see graph on right). The continuous spectrum is due to bremsstrahlung, while the sharp peaks are characteristic X-rays associated with the atoms in the target.

The spectrum has a sharp cutoff at low wavelength (high frequency), which is due to the limited energy of the incoming electrons. For example, if each electron in the tube is accelerated through 60 kV, then it will acquire a kinetic energy of 60 keV, and when it strikes the target it can create X-ray photons with energy of at most 60 keV, by conservation of energy. (This upper limit corresponds to the electron coming to a stop by emitting just one X-ray photon. Usually the electron emits many photons, and each has an energy less than 60 keV.) A photon with energy of 60 keV or less has a wavelength of 21 pm or more, so the X-ray spectrum has exactly that cutoff, as seen in the graph. This cutoff applies to both the continuous (bremsstrahlung) spectrum and the characteristic sharp peaks: There is no X-ray of any kind beyond the cutoff. However, the cutoff is most obvious for the continuous spectrum.

The exact formula for the cutoff comes from setting equal the kinetic energy of the electron, E = eV, and the energy of the X-ray photon, E = = hc/λ.

## References

1. ^ William Duane and Franklin L. Hunt (1915). "On X-Ray Wave-Lengths".
2. ^ Handbook of X-ray spectrometry by René Grieken, Andrzej Markowicz, page 3, Google books link
This article was sourced from Creative Commons Attribution-ShareAlike License; additional terms may apply. World Heritage Encyclopedia content is assembled from numerous content providers, Open Access Publishing, and in compliance with The Fair Access to Science and Technology Research Act (FASTR), Wikimedia Foundation, Inc., Public Library of Science, The Encyclopedia of Life, Open Book Publishers (OBP), PubMed, U.S. National Library of Medicine, National Center for Biotechnology Information, U.S. National Library of Medicine, National Institutes of Health (NIH), U.S. Department of Health & Human Services, and USA.gov, which sources content from all federal, state, local, tribal, and territorial government publication portals (.gov, .mil, .edu). Funding for USA.gov and content contributors is made possible from the U.S. Congress, E-Government Act of 2002.

Crowd sourced content that is contributed to World Heritage Encyclopedia is peer reviewed and edited by our editorial staff to ensure quality scholarly research articles.